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Essays in Open Box Problem category
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An Open Box Problem
... = Length - (2 * Cut Out) * Width - (2 * Cut Out) * Height Using a square, both the length & the width are equal. I am using a length/width of 20cm. I am going to call the ...
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Area & Volume Exploration – Component proportional changes
... decreasing. This means the Maximum volume lies below 17.5. As the volume rises between 12.5 and 15 we know that the maximum volume must lie after 12.5. We can now continue with the trial and improvement table to fin the ...
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Boxed In.
... volume is at its highest between the cut out of 3 and 4cm. I will now use trial and improvement method to work out the maximum volume. I will work between the cut outs 3 and 4 centimetres. To get the Length/Breath ...
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Global warming is an important factor because every one in the world but most importantly for me it will effect all of my relatives, as it is predicted that countries such as Bangladesh will be totally fooled due to global warming.
... ...
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Histoire
... in ruins. Also, Germany had deliberately blown up many of the French railways. Therefore, Clemenceau wanted a harsh treaty; he wanted Germany to pay all the damaged caused during the war. He also wanted Germany to be permanently weakened so ...
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In this coursework my task description is to see how fast I can catch a reaction time ruler. I have to do this with both my hands and see the difference between the hands.
... 3 RIGHT HAND LEFT HAND RIGHT HAND LEFT HAND RIGHT HAND LEFT HAND 9 8 14 16.5 17.5 19 11 14 16 11 8 14 19.5 11 11 16 13.5 14 14 15 15 17 14 11 8 11 19 17.5 14.5 9 14 15.5 8 9 16 17.5 18.5 19 14 9 14 19 17 15.5 14 11.5 10 10 9 11 15 11 14 16 16 19 22 20 11 9 WOMAN 1 WOMAN 2 WOMAN 3 RIGHT HAND LEFT HAND RIGHT HAND LEFT HAND RIGHT HAND LEFT HAND 10 12 13 14 15.5 17.5 19 20.5 11 9 19 17 10 13 12 15 11 9 8 17 12 11 14 8 11 17 16 11 6 13 8 7 11 12 17 15.5 16 17 8 11 19 17 20.5 21.5 9 8 7 11 12 17 18 17 8 7 11 19 20.5 11 11 16 PREDICTION I PREDICT THAT YOUR WRITING HAND IS YOUR DOMINANT HAND AS I THINK THAT YOU REACT FASTER TO THAT HAND BECAUSE YOU ARE USE ...
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Investigate the volume of an open box constructed by one piece of rectangular card that has all four corners having had squares cut out of them.
... included in this diagram the labels c, x and y, these show the cut out size and the original length and width of the card, I will now need to show the values of the width, length and height in ...
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Investigation: The open box problem.
... will determine the size of x that will give the highest volume to 2d.p. After finding the highest value of X I will prove that my answer if right by using differentiation. Finally I will try and find a rule ...
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Kunstnik ja dekoraator.
... unustama panevad. Siin oli aga tegu ühe suure teleteatriga. Arvan, et mina ei olnud ainuke, kellel näiteks stseenis, kus Ahast taga aetakse, tekkis kriipiv ja kahtlustav tunne , mis ütleb:"Vaata, vot selle aia taga seisab uus mersu ja tolle kuuri taga ...
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Maths Courseowrk - Open Box
... drawn the tables I will analyze the graphs. I will put the graphs under the table so on the next few pages there will be a table of values showing the different volumes depending on the cut out of the ...
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Open Box Problem
... = Length - (2 * Cut Out) * Width - (2 * Cut Out) * Height Using a square, both the length & the width are equal. I am using a length/width of 20cm. I am going to call the ...
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Open Box Problem
... Width * Height (where * is multiplication) To show a simple example of how this formula works with the open box, I will first of all use a initial piece of card that is 20cm by 20 cm, and a corner square ...
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Open Box Problem
... the greatest volume to 3 decimal places. To create the box, the equal size squares are cut from the four corners of the card, and it is then folded along the dotted lines. I then put the resultant data into tables to ...
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Open box Problem.
... we can get the maximum volume in integer. Now I am going to find out the volume when X is between 3.5 and 4.5. Here are the results: X(cm) X(24cm-2X)(cm) 3.5 1011.5 3.6 1016.064 3.7 1019.572 3.8 1022.048 3.9 1023.516 4.0 1024 4.1 1023.524 4.2 1022.112 4.3 1019.788.4.4 4.4 1016.516 4.5 1012.5 We found out that 4cm is still the biggest value whereas we can get the ...
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Open Box Problem.
... sizes I will look for patterns and try to formulate a rule to work out the largest volume for an open box square. The sizes that I will be using are: 1. 20 x 20 2. 40 x 40 3. ...
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Tbe Open Box Problem
... is therefore 1.67. I will now go into even smaller numbers between 1.66 and 1.67. Cut off (cm) width (cm) length (cm) height (cm) volume (cm²) 1.661 6.678 6.678 1.661 74.0734 1.662 6.676 6.676 1.662 740736 1.663 6.674 6.674 1.663 74.0738 1.664 6.672 6.672 1.664 74.0739 1.665 6.67 6.67 1.665 74.074 1.666 6.668 6.668 1.666 74.074065 1.667 6.666 6.666 1.667 74.074072 1.668 6.664 6.664 1.668 74.074 1.669 6.662 6.662 1.669 74.074 The highest is 1.667. I will show the graph to show the change in volume for a 10 by 10 ...
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The Open Box Problem
... is increased until the resulting volume goes down. This step is repeated to one and then two decimal places, giving the optimum side length to 3.33 cm as the maximum volume. The results for different length squares can be worked ...
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The Open Box Problem
... until the resulting volume goes down. This step is repeated to one and then two decimal places, giving the optimum side length to 3.33 cm as the maximum volume. The results for different length squares can be worked out, collected ...
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The Open Box Problem
... (cm) W L V (cm3) 4 22 22 1936 5 20 20 2000 6 18 18 1944 7 16 16 1792 8 14 14 1568 This is a spreadsheet, where the value of the volume is a product of the cut size, the width and the length. The formula used in the spreadsheet is: V = Cut size x W x L (on ...
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The Open Box Problem
... x Width - (2 x Cut Out) x Height (Cut Out) Using a square, both the length & the width are equal. I am using a length and width of 24cm. I am going to call the cut out "x." ...
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The Open Box Problem
... (2 * Cut Out) * Width - (2 * Cut Out) * Height Using a square, both the length & the width are equal. I am using a length/width of 20cm. I am going to call the cut out "x." ...
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The Open Box Problem
... until the resulting volume goes down. This step is repeated to one and then two decimal places, giving the optimum side length to 3.33 cm as the maximum volume. The results for different length squares can be worked out, collected ...
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The Open Box Problem
... Using this sized length will allow me to only cut off each corner up to 9.9cm as otherwise I will cause me to run out of card. I am going to begin by looking at cutting the squares off as ...
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The Open Box Problem
... (2 * Cut Out) * Width - (2 * Cut Out) * Height Using a square, both the length & the width are equal. I am using a length/width of 20cm. I am going to call the cut out "x." ...
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The Open Box Problem
... the following equation. Volume = Length -- (2 * Cut Out) * Width -- (2 * Cut Out) * Height Using a square, both the length & the width are equal. I am using a length/width of 20cm. I am going ...
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