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Words: | Submitted: Mon Sep 29 2003
... graphs and the gradient function at each point in a curve is different therefore I will draw tangents using a capillary tube and calculate the gradient by taking the change in the value of the y co ordinates divided by the change in t value of the x co ordinates. I would then choose n = 3 for varying values of "a". The equations would be ; y = x3, y = 2x3,y = 3x3. Again these equations would get me curved graphs and I will establish a relationship Between the curve and the gradient. In order to calculate the gradient in a curve , we know we have to draw the tangent for a given point x and then calculate the gradient. The gradient can be calculated by the change in the y co-ordinates divided by the change in the x co-ordinates. I will now draw graphs for the equations I stated above: Using a ...
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