... will be using. The molar mass of calcium hydroxide is: C = 40 O = 16 (x2) H = 1 (x2) R.A.M = 74 The concentration of calcium hydroxide at the beginning will be: 1.5 / 74 = 0.02 So, the concentration is 0.02 mol/dm3 In the experiment I will be using 25cm3 of the solution from the volumetric flask, so the mass of the calcium hydroxide in one titration will be: 0.375 / 10 = 0.0375g Therefore the number of moles of calcium hydroxide: 0.0375 / 74 = 0.0005 moles Ca(OH)2(aq) + 2HCl --> CaCl2(aq) + 2H20(l) As seen from the equation the ratio of hydrochloric acid to calcium hydroxide is 2:1, therefore we need twice as much hydrochloric acid. The number of moles of hydrochloric acid required to react with 0.0005 moles of calcium hydroxide will be: 0.0005 x 2 = 0.001 moles Ideally we will want the same volume of hydrochloric acid reacting with calcium hydroxide, which is 25cm3 and ...

See this essay or coursework document in full right now